15x^2=121

Solution for 15x^2=121 equation:

15x^2=121

We move all terms to the left:

15x^2-(121)=0

a = 15; b = 0; c = -121;
Δ = b2-4ac
Δ = 02-4·15·(-121)
Δ = 7260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7260}=\sqrt{484*15}=\sqrt{484}*\sqrt{15}=22\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-22\sqrt{15}}{2*15}=\frac{0-22\sqrt{15}}{30}
=-\frac{22\sqrt{15}}{30}
=-\frac{11\sqrt{15}}{15}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+22\sqrt{15}}{2*15}=\frac{0+22\sqrt{15}}{30}
=\frac{22\sqrt{15}}{30}
=\frac{11\sqrt{15}}{15}
$